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76 lines
2.5 KiB
Python
76 lines
2.5 KiB
Python
from string import ascii_uppercase
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def mixed_keyword(
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keyword: str, plaintext: str, verbose: bool = False, alphabet: str = ascii_uppercase
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) -> str:
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"""
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For keyword: hello
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H E L O
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A B C D
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F G I J
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K M N P
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Q R S T
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U V W X
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Y Z
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and map vertically
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>>> mixed_keyword("college", "UNIVERSITY", True) # doctest: +NORMALIZE_WHITESPACE
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{'A': 'C', 'B': 'A', 'C': 'I', 'D': 'P', 'E': 'U', 'F': 'Z', 'G': 'O', 'H': 'B',
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'I': 'J', 'J': 'Q', 'K': 'V', 'L': 'L', 'M': 'D', 'N': 'K', 'O': 'R', 'P': 'W',
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'Q': 'E', 'R': 'F', 'S': 'M', 'T': 'S', 'U': 'X', 'V': 'G', 'W': 'H', 'X': 'N',
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'Y': 'T', 'Z': 'Y'}
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'XKJGUFMJST'
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>>> mixed_keyword("college", "UNIVERSITY", False) # doctest: +NORMALIZE_WHITESPACE
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'XKJGUFMJST'
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"""
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keyword = keyword.upper()
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plaintext = plaintext.upper()
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alphabet_set = set(alphabet)
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# create a list of unique characters in the keyword - their order matters
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# it determines how we will map plaintext characters to the ciphertext
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unique_chars = []
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for char in keyword:
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if char in alphabet_set and char not in unique_chars:
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unique_chars.append(char)
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# the number of those unique characters will determine the number of rows
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num_unique_chars_in_keyword = len(unique_chars)
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# create a shifted version of the alphabet
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shifted_alphabet = unique_chars + [
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char for char in alphabet if char not in unique_chars
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]
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# create a modified alphabet by splitting the shifted alphabet into rows
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modified_alphabet = [
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shifted_alphabet[k : k + num_unique_chars_in_keyword]
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for k in range(0, 26, num_unique_chars_in_keyword)
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]
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# map the alphabet characters to the modified alphabet characters
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# going 'vertically' through the modified alphabet - consider columns first
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mapping = {}
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letter_index = 0
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for column in range(num_unique_chars_in_keyword):
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for row in modified_alphabet:
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# if current row (the last one) is too short, break out of loop
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if len(row) <= column:
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break
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# map current letter to letter in modified alphabet
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mapping[alphabet[letter_index]] = row[column]
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letter_index += 1
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if verbose:
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print(mapping)
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# create the encrypted text by mapping the plaintext to the modified alphabet
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return "".join(mapping.get(char, char) for char in plaintext)
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if __name__ == "__main__":
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# example use
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print(mixed_keyword("college", "UNIVERSITY"))
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