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* Added code for palindrome partitioning problem under dynamic programming * Updated return type for function * Updated Line 24 according to suggestions * Apply suggestions from code review Co-authored-by: Caeden Perelli-Harris <caedenperelliharris@gmail.com> * Update palindrome_partitioning.py * Update palindrome_partitioning.py * is_palindromic Co-authored-by: Christian Clauss <cclauss@me.com> Co-authored-by: Caeden Perelli-Harris <caedenperelliharris@gmail.com>
40 lines
1.2 KiB
Python
40 lines
1.2 KiB
Python
"""
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Given a string s, partition s such that every substring of the
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partition is a palindrome.
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Find the minimum cuts needed for a palindrome partitioning of s.
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Time Complexity: O(n^2)
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Space Complexity: O(n^2)
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For other explanations refer to: https://www.youtube.com/watch?v=_H8V5hJUGd0
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"""
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def find_minimum_partitions(string: str) -> int:
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"""
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Returns the minimum cuts needed for a palindrome partitioning of string
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>>> find_minimum_partitions("aab")
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1
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>>> find_minimum_partitions("aaa")
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0
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>>> find_minimum_partitions("ababbbabbababa")
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3
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"""
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length = len(string)
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cut = [0] * length
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is_palindromic = [[False for i in range(length)] for j in range(length)]
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for i, c in enumerate(string):
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mincut = i
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for j in range(i + 1):
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if c == string[j] and (i - j < 2 or is_palindromic[j + 1][i - 1]):
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is_palindromic[j][i] = True
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mincut = min(mincut, 0 if j == 0 else (cut[j - 1] + 1))
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cut[i] = mincut
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return cut[length - 1]
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if __name__ == "__main__":
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s = input("Enter the string: ").strip()
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ans = find_minimum_partitions(s)
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print(f"Minimum number of partitions required for the '{s}' is {ans}")
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