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* isort --profile black --recursive . * Update codespell.yml * typo: vertices * typo: Explanation * typo: Explanation * Fix typos
59 lines
1.4 KiB
Python
59 lines
1.4 KiB
Python
"""
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https://en.wikipedia.org/wiki/Component_(graph_theory)
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Finding connected components in graph
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"""
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test_graph_1 = {0: [1, 2], 1: [0, 3], 2: [0], 3: [1], 4: [5, 6], 5: [4, 6], 6: [4, 5]}
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test_graph_2 = {0: [1, 2, 3], 1: [0, 3], 2: [0], 3: [0, 1], 4: [], 5: []}
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def dfs(graph: dict, vert: int, visited: list) -> list:
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"""
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Use depth first search to find all vertices
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being in the same component as initial vertex
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>>> dfs(test_graph_1, 0, 5 * [False])
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[0, 1, 3, 2]
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>>> dfs(test_graph_2, 0, 6 * [False])
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[0, 1, 3, 2]
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"""
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visited[vert] = True
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connected_verts = []
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for neighbour in graph[vert]:
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if not visited[neighbour]:
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connected_verts += dfs(graph, neighbour, visited)
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return [vert] + connected_verts
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def connected_components(graph: dict) -> list:
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"""
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This function takes graph as a parameter
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and then returns the list of connected components
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>>> connected_components(test_graph_1)
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[[0, 1, 3, 2], [4, 5, 6]]
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>>> connected_components(test_graph_2)
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[[0, 1, 3, 2], [4], [5]]
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"""
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graph_size = len(graph)
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visited = graph_size * [False]
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components_list = []
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for i in range(graph_size):
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if not visited[i]:
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i_connected = dfs(graph, i, visited)
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components_list.append(i_connected)
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return components_list
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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