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d2f7982a4e
Use pythons complex number module cmath for the calculation of the roots
38 lines
907 B
Python
38 lines
907 B
Python
from cmath import sqrt
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from typing import Tuple
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def quadratic_roots(a: int, b: int, c: int) -> Tuple[complex, complex]:
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"""
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Given the numerical coefficients a, b and c,
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calculates the roots for any quadratic equation of the form ax^2 + bx + c
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>>> quadratic_roots(a=1, b=3, c=-4)
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(1.0, -4.0)
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>>> quadratic_roots(5, 6, 1)
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(-0.2, -1.0)
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>>> quadratic_roots(1, -6, 25)
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((3+4j), (3-4j))
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"""
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if a == 0:
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raise ValueError("Coefficient 'a' must not be zero.")
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delta = b * b - 4 * a * c
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root_1 = (-b + sqrt(delta)) / (2 * a)
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root_2 = (-b - sqrt(delta)) / (2 * a)
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return (
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root_1.real if not root_1.imag else root_1,
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root_2.real if not root_2.imag else root_2,
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)
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def main():
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solutions = quadratic_roots(a=5, b=6, c=1)
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print("The solutions are: {} and {}".format(*solutions))
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if __name__ == "__main__":
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main()
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