Python/dynamic_programming/longest_increasing_subsequence_o(nlogn).py
2019-10-05 10:14:13 +05:00

42 lines
947 B
Python

#############################
# Author: Aravind Kashyap
# File: lis.py
# comments: This programme outputs the Longest Strictly Increasing Subsequence in O(NLogN)
# Where N is the Number of elements in the list
#############################
def CeilIndex(v, l, r, key):
while r - l > 1:
m = (l + r) / 2
if v[m] >= key:
r = m
else:
l = m
return r
def LongestIncreasingSubsequenceLength(v):
if len(v) == 0:
return 0
tail = [0] * len(v)
length = 1
tail[0] = v[0]
for i in range(1, len(v)):
if v[i] < tail[0]:
tail[0] = v[i]
elif v[i] > tail[length - 1]:
tail[length] = v[i]
length += 1
else:
tail[CeilIndex(tail, -1, length - 1, v[i])] = v[i]
return length
if __name__ == "__main__":
v = [2, 5, 3, 7, 11, 8, 10, 13, 6]
print(LongestIncreasingSubsequenceLength(v))