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self assessment

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Sebastian Raschka 2014-04-29 09:53:17 -04:00
parent ccb3947fde
commit 4dac403cdc
1 changed files with 95 additions and 4 deletions
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99
tutorials/scope_resolution_legb_rule.ipynb
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@ -62,6 +62,7 @@
"- [1. LG - Local vs. Global](#section_1) \n",
"- [2. LEG - Local, Enclosed, and Global scope](#section_2) \n",
"- [3. LEGB - Local, Enclosed, Global, Built-in](#section_3) \n",
"- [Self-assessment exercise](#assessment)\n",
"- [Conclusion](#conclusion) \n",
"- [Solutions](#solutions)"
]
@ -498,8 +499,6 @@
"input": [
"a_var = 'global variable'\n",
"\n",
"\n",
"\n",
"def len(in_var):\n",
" print('called my len() function')\n",
" l = 0\n",
@ -511,8 +510,7 @@
" len_in_var = len(in_var)\n",
" print('Input variable is of length', len_in_var)\n",
"\n",
"#a_func('Hello, World!')\n",
" "
"#a_func('Hello, World!')"
],
"language": "python",
"metadata": {},
@ -550,6 +548,65 @@
"Since the exact same names can be used to map names to different objects - as long as the names are in different name spaces - there is no problem of reusing the name `len` to define our own length function (this is just for demonstration pruposes, it is NOT recommended). As we go up in Python's L -> E -> G -> B hierarchy, the function `a_func()` finds `len()` already in the global scope first before it attempts"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<a name =\"assessment\"></a>\n",
"<br>\n",
"<br>"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Self-assessment exercise"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"Now, after we went through a couple of exercises, let us quickly check where we are. So, one more time: What would the following code print out?"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"a = 'global'\n",
"\n",
"def outer():\n",
" \n",
" def len(in_var):\n",
" print('called my len() function: ', end=\"\")\n",
" l = 0\n",
" for i in in_var:\n",
" l += 1\n",
" return l\n",
" \n",
" a = 'local'\n",
" \n",
" def inner():\n",
" global len\n",
" nonlocal a\n",
" a += ' variable'\n",
" inner()\n",
" print('a is', a)\n",
" print(len(a))\n",
"\n",
"\n",
"outer()\n",
"\n",
"print(len(a))\n",
"print('a is', a)"
],
"language": "python",
"metadata": {},
"outputs": [],
"prompt_number": 59
},
{
"cell_type": "markdown",
"metadata": {},
@ -559,6 +616,13 @@
"<br>"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"[[go to solution](#solutions)]"
]
},
{
"cell_type": "markdown",
"metadata": {},
@ -675,6 +739,33 @@
"metadata": {},
"outputs": [],
"prompt_number": 9
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Execute to run the self-assessment solution\n",
"\n",
"sol = \"000010100110111101110101011101000110010101110010001010\"\\\n",
"\"0000101001001110100000101000001010011000010010000001101001011100110\"\\\n",
"\"0100000011011000110111101100011011000010110110000100000011101100110\"\\\n",
"\"0001011100100110100101100001011000100110110001100101000010100110001\"\\\n",
"\"1011000010110110001101100011001010110010000100000011011010111100100\"\\\n",
"\"1000000110110001100101011011100010100000101001001000000110011001110\"\\\n",
"\"1010110111001100011011101000110100101101111011011100011101000100000\"\\\n",
"\"0011000100110100000010100000101001100111011011000110111101100010011\"\\\n",
"\"0000101101100001110100000101000001010001101100000101001100001001000\"\\\n",
"\"0001101001011100110010000001100111011011000110111101100010011000010\"\\\n",
"\"1101100\"\n",
"\n",
"sol_str =''.join(chr(int(sol[i:i+8], 2)) for i in range(0, len(sol), 8))\n",
"for line in sol_str.split('\\n'):\n",
" print(line)"
],
"language": "python",
"metadata": {},
"outputs": [],
"prompt_number": 58
}
],
"metadata": {}