numpy nan quickguide

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rasbt 2014-07-30 15:32:25 -04:00
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- A collection of useful regular expressions [[IPython nb](http://nbviewer.ipython.org/github/rasbt/python_reference/blob/master/tutorials/useful_regex.ipynb)]
- Quick guide for dealing with missing numbers in NumPy [[IPython nb](http://nbviewer.ipython.org/github/rasbt/python_reference/blob/master/tutorials/numpy_nan_quickguide.ipynb)]
<br>

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"[[back to python_reference](https://github.com/rasbt/python_reference)]"
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"Last updated: 30/07/2014 \n",
"\n",
"CPython 3.4.1\n",
"IPython 2.0.0\n",
"\n",
"numpy 1.8.1\n"
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"source": [
"<font size=\"1.5em\">[More information](https://github.com/rasbt/watermark) about the `watermark` magic command extension.</font>"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<br>\n",
"<br>"
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"source": [
"Quick guide for dealing with missing numbers in NumPy"
]
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{
"cell_type": "markdown",
"metadata": {},
"source": [
"This is just a quick overview of how to deal with missing values (i.e., \"NaN\"s for \"Not-a-Number\") in NumPy and I am happy to expand it over time. Yes, and there will also be a separate one for pandas some time!\n",
"\n",
"I would be happy to hear your comments and suggestions. \n",
"Please feel free to drop me a note via\n",
"[twitter](https://twitter.com/rasbt), [email](mailto:bluewoodtree@gmail.com), or [google+](https://plus.google.com/+SebastianRaschka).\n",
"<hr>"
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"cell_type": "heading",
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"Sections"
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"- [Sample data from a CSV file](#Sample-data-from-a-CSV-file)\n",
"- [Determining if a value is missing](#Determining-if-a-value-is-missing)\n",
"- [Counting the number of missing values](#Counting-the-number-of-missing-values)\n",
"- [Calculating the sum of an array that contains NaNs](#Calculating the sum of an array that contains NaNs)\n",
"- [Removing all rows that contain missing values](#Removing-all-rows-that-contain-missing-values)\n",
"- [Convert missing values to 0](#Convert-missing-values-to-0)\n",
"- [Converting certain numbers to NaN](#Converting-certain-numbers-to-NaN)\n",
"- [Remove all missing elements from an array](#Remove-all-missing-elements-from-an-array)\n"
]
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{
"cell_type": "markdown",
"metadata": {},
"source": [
"<br>\n",
"<br>"
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"cell_type": "heading",
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"Sample data from a CSV file"
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"metadata": {},
"source": [
"[[back to top](#Sections)]"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"Let's assume that we have a CSV file with missing elements like the one shown below."
]
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"source": [
"\n",
"<br>"
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"cell_type": "code",
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"input": [
"%%file example.csv\n",
"1,2,3,4\n",
"5,6,,8\n",
"10,11,12,"
],
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"outputs": [
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"output_type": "stream",
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"text": [
"Overwriting example.csv\n"
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"source": [
"The `np.genfromtxt` function has a `missing_values` parameters which translates missing values into `np.nan` objects by default. This allows us to construct a new NumPy `ndarray` object, even if elements are missing."
]
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"\n",
"<br>"
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"input": [
"import numpy as np\n",
"ary = np.genfromtxt('./example.csv', delimiter=',')\n",
"\n",
"print('%s x %s array:\\n' %(ary.shape[0], ary.shape[1]))\n",
"print(ary)"
],
"language": "python",
"metadata": {},
"outputs": [
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"output_type": "stream",
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"text": [
"3 x 4 array:\n",
"\n",
"[[ 1. 2. 3. 4.]\n",
" [ 5. 6. nan 8.]\n",
" [ 10. 11. 12. nan]]\n"
]
}
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{
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"metadata": {},
"source": [
"<br>\n",
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"cell_type": "heading",
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"source": [
"Determining if a value is missing"
]
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{
"cell_type": "markdown",
"metadata": {},
"source": [
"[[back to top](#Sections)]"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"A handy function to test whether a value is a `NaN` or not is to use the `np.isnan` function."
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<br>"
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},
{
"cell_type": "code",
"collapsed": false,
"input": [
"np.isnan(np.nan)"
],
"language": "python",
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{
"metadata": {},
"output_type": "pyout",
"prompt_number": 37,
"text": [
"True"
]
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{
"cell_type": "markdown",
"metadata": {},
"source": [
"<br>"
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{
"cell_type": "markdown",
"metadata": {},
"source": [
"It is especially useful to create boolean masks for the so-called \"fancy indexing\" of NumPy arrays, which we will come back to later."
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"np.isnan(ary)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"metadata": {},
"output_type": "pyout",
"prompt_number": 5,
"text": [
"array([[False, False, False, False],\n",
" [False, False, True, False],\n",
" [False, False, False, True]], dtype=bool)"
]
}
],
"prompt_number": 5
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<br>\n",
"<br>"
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{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Counting the number of missing values"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"[[back to top](#Sections)]"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"In order to find out how many elements are missing in our array, we can use the `np.isnan` function that we have seen in the previous section. "
]
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{
"cell_type": "markdown",
"metadata": {},
"source": [
"<br>"
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"cell_type": "code",
"collapsed": false,
"input": [
"np.count_nonzero(np.isnan(ary))"
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"metadata": {},
"output_type": "pyout",
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"text": [
"2"
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"source": [
"<br>\n"
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"source": [
"If we want to determine the number of non-missing elements, we can simply revert the returned `Boolean` mask via the handy \"tilde\" sign."
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"cell_type": "code",
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"input": [
"np.count_nonzero(~np.isnan(ary))"
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"10"
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"source": [
"<br>\n",
"<br>"
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"cell_type": "heading",
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"source": [
"Calculating the sum of an array that contains `NaN`s"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"[[back to top](#Sections)]"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"As we will find out via the following code snippet, we can't use NumPy's regular `sum` function to calculate the sum of an array."
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"input": [
"np.sum(ary)"
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"text": [
"nan"
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"metadata": {},
"source": [
"<br>"
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"source": [
"Since the `np.sum` function does not work, use `np.nansum` instead:"
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"print('total sum:', np.nansum(ary))"
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"output_type": "stream",
"stream": "stdout",
"text": [
"total sum: 62.0\n"
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"input": [
"print('row sums:', np.nansum(ary, axis=0))"
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"output_type": "stream",
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"text": [
"row sums: [ 16. 19. 15. 12.]\n"
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"input": [
"print('column sums:', np.nansum(ary, axis=1))"
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"output_type": "stream",
"stream": "stdout",
"text": [
"column sums: [ 10. 19. 33.]\n"
]
}
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"source": [
"<br>\n",
"<br>"
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"cell_type": "heading",
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"source": [
"Removing all rows that contain missing values"
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{
"cell_type": "markdown",
"metadata": {},
"source": [
"[[back to top](#Sections)]"
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{
"cell_type": "markdown",
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"source": [
"Here, we will use the `Boolean mask` again to return only those rows that DON'T contain missing values. And if we want to get only the rows that contain `NaN`s, we could simply drop the `~`."
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"metadata": {},
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"text": [
"array([[ 1., 2., 3., 4.]])"
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"cell_type": "markdown",
"metadata": {},
"source": [
"<br>\n",
"<br>"
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"cell_type": "heading",
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"Convert missing values to 0"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"[[back to top](#Sections)]"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"Certain operations, algorithms, and other analyses might not work with `NaN` objects in our data array. But that's not a problem: We can use the convenient `np.nan_to_num` function will convert it to the value 0."
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"cell_type": "markdown",
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"source": [
"<br>"
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"cell_type": "code",
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"input": [
"ary0 = np.nan_to_num(ary)\n",
"ary0"
],
"language": "python",
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"outputs": [
{
"metadata": {},
"output_type": "pyout",
"prompt_number": 15,
"text": [
"array([[ 1., 2., 3., 4.],\n",
" [ 5., 6., 0., 8.],\n",
" [ 10., 11., 12., 0.]])"
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],
"prompt_number": 15
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{
"cell_type": "markdown",
"metadata": {},
"source": [
"<br>\n",
"<br>"
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"cell_type": "heading",
"level": 2,
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"source": [
"Converting certain numbers to NaN"
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{
"cell_type": "markdown",
"metadata": {},
"source": [
"[[back to top](#Sections)]"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"Vice versa, we can also convert any number to a `np.NaN` object. Here, we use the array that we created in the previous section and convert the `0`s back to `np.nan` objects."
]
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"metadata": {},
"source": [
"<br>"
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"cell_type": "code",
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"input": [
"ary0[ary0==0] = np.nan\n",
"ary0"
],
"language": "python",
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{
"metadata": {},
"output_type": "pyout",
"prompt_number": 16,
"text": [
"array([[ 1., 2., 3., 4.],\n",
" [ 5., 6., nan, 8.],\n",
" [ 10., 11., 12., nan]])"
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"source": [
"<br>\n",
"<br>"
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"Remove all missing elements from an array"
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"cell_type": "markdown",
"metadata": {},
"source": [
"[[back to top](#Sections)]"
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"source": [
"This is one is a little bit more tricky. We can remove missing values via a combination of the `Boolean` mask and fancy indexing, however, this will have the disadvantage that it will flatten our array (we can't just punch holes into a NumPy array)."
]
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"cell_type": "code",
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"input": [
"ary[~np.isnan(ary)]"
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{
"metadata": {},
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"prompt_number": 17,
"text": [
"array([ 1., 2., 3., 4., 5., 6., 8., 10., 11., 12.])"
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"source": [
"Thus, this is a method that would better work on individual rows:"
]
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"cell_type": "code",
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"input": [
"x = np.array([1,2,np.nan])\n",
"\n",
"x[~np.isnan(np.array(x))]"
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{
"metadata": {},
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"array([ 1., 2.])"
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