mirror of
https://github.com/TheAlgorithms/Python.git
synced 2024-11-23 21:11:08 +00:00
code enhancement in sort.double_sort
(#10798)
* don't need to return list because list is mutable * Don't need to return list as list is mutable * use advantage of python in swapping * filter blank inputs from input list * minor changes * minor mistake * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * more readable * Update double_sort.py * last fixes * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * Apply suggestions from code review * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci --------- Co-authored-by: pre-commit-ci[bot] <66853113+pre-commit-ci[bot]@users.noreply.github.com> Co-authored-by: Christian Clauss <cclauss@me.com>
This commit is contained in:
parent
a8b6bda993
commit
417b7edfc3
|
@ -1,4 +1,7 @@
|
|||
def double_sort(lst):
|
||||
from typing import Any
|
||||
|
||||
|
||||
def double_sort(collection: list[Any]) -> list[Any]:
|
||||
"""This sorting algorithm sorts an array using the principle of bubble sort,
|
||||
but does it both from left to right and right to left.
|
||||
Hence, it's called "Double sort"
|
||||
|
@ -14,29 +17,28 @@ def double_sort(lst):
|
|||
>>> double_sort([-3, 10, 16, -42, 29]) == sorted([-3, 10, 16, -42, 29])
|
||||
True
|
||||
"""
|
||||
no_of_elements = len(lst)
|
||||
no_of_elements = len(collection)
|
||||
for _ in range(
|
||||
int(((no_of_elements - 1) / 2) + 1)
|
||||
): # we don't need to traverse to end of list as
|
||||
for j in range(no_of_elements - 1):
|
||||
if (
|
||||
lst[j + 1] < lst[j]
|
||||
): # applying bubble sort algorithm from left to right (or forwards)
|
||||
temp = lst[j + 1]
|
||||
lst[j + 1] = lst[j]
|
||||
lst[j] = temp
|
||||
if (
|
||||
lst[no_of_elements - 1 - j] < lst[no_of_elements - 2 - j]
|
||||
): # applying bubble sort algorithm from right to left (or backwards)
|
||||
temp = lst[no_of_elements - 1 - j]
|
||||
lst[no_of_elements - 1 - j] = lst[no_of_elements - 2 - j]
|
||||
lst[no_of_elements - 2 - j] = temp
|
||||
return lst
|
||||
# apply the bubble sort algorithm from left to right (or forwards)
|
||||
if collection[j + 1] < collection[j]:
|
||||
collection[j], collection[j + 1] = collection[j + 1], collection[j]
|
||||
# apply the bubble sort algorithm from right to left (or backwards)
|
||||
if collection[no_of_elements - 1 - j] < collection[no_of_elements - 2 - j]:
|
||||
(
|
||||
collection[no_of_elements - 1 - j],
|
||||
collection[no_of_elements - 2 - j],
|
||||
) = (
|
||||
collection[no_of_elements - 2 - j],
|
||||
collection[no_of_elements - 1 - j],
|
||||
)
|
||||
return collection
|
||||
|
||||
|
||||
if __name__ == "__main__":
|
||||
print("enter the list to be sorted")
|
||||
lst = [int(x) for x in input().split()] # inputing elements of the list in one line
|
||||
sorted_lst = double_sort(lst)
|
||||
# allow the user to input the elements of the list on one line
|
||||
unsorted = [int(x) for x in input("Enter the list to be sorted: ").split() if x]
|
||||
print("the sorted list is")
|
||||
print(sorted_lst)
|
||||
print(f"{double_sort(unsorted) = }")
|
||||
|
|
Loading…
Reference in New Issue
Block a user