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Problem 16 Added

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Solution to the Problem 16  has been added.
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Thejus-Paul 2017-11-20 01:34:21 +05:30
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commit c787a22d93
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15
Project Euler/Problem 16/sol1.py Normal file
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@ -0,0 +1,15 @@
power = int(input("Enter the power of 2: "))
num = 2**power
string_num = str(num)
list_num = list(string_num)
sum_of_num = 0
print("2 ^",power,"=",num)
for i in list_num:
sum_of_num += int(i)
print("Sum of the digits are:",sum_of_num)

3
Project Euler/README.md
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@ -49,3 +49,6 @@ PROBLEMS:
Using the rule above and starting with 13, we generate the following sequence: Using the rule above and starting with 13, we generate the following sequence:
13 → 40 → 20 → 10 → 5 → 16 → 8 → 4 → 2 → 1 13 → 40 → 20 → 10 → 5 → 16 → 8 → 4 → 2 → 1
Which starting number, under one million, produces the longest chain? Which starting number, under one million, produces the longest chain?
16. 2^15 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26.
What is the sum of the digits of the number 2^1000?