Python/project_euler/problem_207/sol1.py
PetitNigaud 99adac0eb1
Add first solution for Project Euler Problem 207 (#3522)
* add solution to Project Euler problem 206

* Add solution to Project Euler problem 205

* updating DIRECTORY.md

* updating DIRECTORY.md

* Revert "Add solution to Project Euler problem 205"

This reverts commit 64e3d36cab.

* Revert "add solution to Project Euler problem 206"

This reverts commit 53568cf4ef.

* add solution for project euler problem 207

* updating DIRECTORY.md

* add type hint for output of helper function

* Correct default parameter value in solution

* use descriptive variable names and remove problem solution from doctest Fixes: #2695

Co-authored-by: nico <esistegal-aber@gmx.de>
Co-authored-by: github-actions <${GITHUB_ACTOR}@users.noreply.github.com>
2020-10-29 12:34:42 +05:30

99 lines
2.7 KiB
Python

"""
Project Euler Problem 207: https://projecteuler.net/problem=207
Problem Statement:
For some positive integers k, there exists an integer partition of the form
4**t = 2**t + k, where 4**t, 2**t, and k are all positive integers and t is a real
number. The first two such partitions are 4**1 = 2**1 + 2 and
4**1.5849625... = 2**1.5849625... + 6.
Partitions where t is also an integer are called perfect.
For any m ≥ 1 let P(m) be the proportion of such partitions that are perfect with
k ≤ m.
Thus P(6) = 1/2.
In the following table are listed some values of P(m)
P(5) = 1/1
P(10) = 1/2
P(15) = 2/3
P(20) = 1/2
P(25) = 1/2
P(30) = 2/5
...
P(180) = 1/4
P(185) = 3/13
Find the smallest m for which P(m) < 1/12345
Solution:
Equation 4**t = 2**t + k solved for t gives:
t = log2(sqrt(4*k+1)/2 + 1/2)
For t to be real valued, sqrt(4*k+1) must be an integer which is implemented in
function check_t_real(k). For a perfect partition t must be an integer.
To speed up significantly the search for partitions, instead of incrementing k by one
per iteration, the next valid k is found by k = (i**2 - 1) / 4 with an integer i and
k has to be a positive integer. If this is the case a partition is found. The partition
is perfect if t os an integer. The integer i is increased with increment 1 until the
proportion perfect partitions / total partitions drops under the given value.
"""
import math
def check_partition_perfect(positive_integer: int) -> bool:
"""
Check if t = f(positive_integer) = log2(sqrt(4*positive_integer+1)/2 + 1/2) is a
real number.
>>> check_partition_perfect(2)
True
>>> check_partition_perfect(6)
False
"""
exponent = math.log2(math.sqrt(4 * positive_integer + 1) / 2 + 1 / 2)
return exponent == int(exponent)
def solution(max_proportion: float = 1 / 12345) -> int:
"""
Find m for which the proportion of perfect partitions to total partitions is lower
than max_proportion
>>> solution(1) > 5
True
>>> solution(1/2) > 10
True
>>> solution(3 / 13) > 185
True
"""
total_partitions = 0
perfect_partitions = 0
integer = 3
while True:
partition_candidate = (integer ** 2 - 1) / 4
# if candidate is an integer, then there is a partition for k
if partition_candidate == int(partition_candidate):
partition_candidate = int(partition_candidate)
total_partitions += 1
if check_partition_perfect(partition_candidate):
perfect_partitions += 1
if perfect_partitions > 0:
if perfect_partitions / total_partitions < max_proportion:
return partition_candidate
integer += 1
if __name__ == "__main__":
print(f"{solution() = }")